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Gramaticaportuguesajosemariarelvaspdf11 ~UPD~
公開日:2023/01/15 / 最終更新日:2023/01/15
Gramaticaportuguesajosemariarelvaspdf11 ~UPD~
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gramaticaportuguesajosemariarelvaspdf11 gramaticaportuguesajosemariarelvaspdf11 gramaticaportuguesajosemariarelvaspdf11Q: Why can’t I create a derived version of typed function in TypeScript I am currently trying to create a separate version of a function that works in a different context and is a little more concise. interface IFoo { (item: T): void; } interface IBar { (item: T): void; } interface ICool { (item: T): void; } function foo(func: IFoo): void { func(null); } function foo2>(func: P): void { func(null); } function foo3>(func: P): void { func(null); } function foo4>(func: P): void { func(null); } //foo type Derived2Foo = IFoo foo(foo2); // error: Can’t convert foo2 to Derived2Foo //foo2 foo(foo2 as Derived2Foo); // error: foo2 is not assignable to inferred type Derived2Foo //foo3 foo(foo3 as ICool); // error: foo3 is not assignable to inferred type ICool //foo4 foo(foo4 as ICool); // error: foo4 is not assignable to inferred type ICool I assume the issue is that because P is already an IFoo in foo3 and foo4 the compiler thinks I am trying to cast a void to an IFoo or a ICool so I cannot create a DerivedFoo that extends from the other. I am wondering if there is some way to create a derived type that is typed. I can’t find any way of doing this, but I’m curious to know if there is any way.
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