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Nagios Xi License Key !!BETTER!! 🤘
公開日:2023/01/14 / 最終更新日:2023/01/14
Nagios Xi License Key !!BETTER!! 🤘
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Nagios Xi License Key
License activation is required for Nagios XI 2011. Reviews (0). Be the first to review this.. 1 crack, password, serial number, registration code or key dfx audio .
License activation is required for Nagios XI 2011. Reviews (0). Be the first to review this.. 1 crack, password, serial number, registration code or key dfx audio .
Software Key to View/Copy Videos. Download Key to View/Copy Videos.. Download Key to View/Copy Videos. However you can use the License that your license is associated with..Q:
Expected Number of Sprinkling
A bag contains $5$ red and $5$ green balls. A ball is chosen at random from the bag. What is the expected number of additional red balls that the bag will contain if another ball is picked?
Answer: $0.5$
My Answer:$\frac{6}{5}\times\frac{5}{4} = \frac{30}{20} = \frac{3}{2}$
Why not $\frac{6}{5}\times\frac{4}{3}=\frac{24}{15}$ or even $\frac{6}{5}\times\frac{10}{9} = \frac{60}{45}$
Any help would be appreciated.
A:
You take $6$ balls out of a bag of $20$, and distribute them in $5$ piles. This is the same as drawing $6$ balls (one for each pile) from a bag of $10$ balls. We are drawing $6$ of the $10$ balls, so the expected number of red balls in a bag after choosing a red ball is $\frac{6}{10}$ or $\frac{6}{10}$.
To evaluate the result, we just use the formula, $E(X) = \frac{1}{1-p}$ where $p$ is the probability of success.
$E(R) = \frac{1}{1-\frac{1}{10}} = \frac{10}{9} = \frac{10}{9}$.
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